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C X g ^ { f B P A @ F s { s h 318 @ 啟 r PF B TEL waisu@quartzocnenjpFree math lessons and math homework help from basic math to algebra, geometry and beyond Students, teachers, parents, and everyone can find solutions to their math problems instantlyInjective, then we can find a 6= b where f(a) = f(b), hence {a,b} ⊂ f −1(f({a})), so C = f (f) fails for C = {a} This shows that if C = f−1(f) always holds, then f is injective Conversely, if f is injective, let x ∈ f−1(f) Then f(x) ∈ f, so f(x) = f(a) for some a ∈ C Hence x = a ∈ C, which means f−1(f) ⊂ C We already know that C ⊂ f−1(f), so this
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